Add algorithm.iteration.foldl
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@ -727,3 +727,56 @@ auto singleton(E)(return ref E element)
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singleChar.popFront();
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assert(singleChar.empty);
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}
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/**
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* Accumulates all elements of a range using a function.
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*
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* $(D_PSYMBOL foldl) takes a function, an input range and the initial value.
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* The function takes this initial value and the first element of the range (in
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* this order), puts them together and returns the result. The return
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* type of the function should be the same as the type of the initial value.
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* This is than repeated for all the remaining elements of the range, whereby
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* the value returned by the passed function is used at the place of the
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* initial value.
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*
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* $(D_PSYMBOL foldl) accumulates from left to right.
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*
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* Params:
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* F = Callable accepting the accumulator and a range element.
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*/
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template foldl(F...)
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if (F.length == 1)
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{
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/**
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* Params:
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* R = Input range type.
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* T = Type of the accumulated value.
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* range = Input range.
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* init = Initial value.
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*
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* Returns: Accumulated value.
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*/
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T foldl(R, T)(R range, auto ref T init)
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if (isInputRange!R && !isInfinite!R)
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{
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if (range.empty)
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{
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return init;
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}
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else
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{
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auto acc = F[0](init, range.front);
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range.popFront;
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return foldl(range, acc);
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}
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}
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}
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///
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@nogc nothrow pure @safe unittest
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{
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int[3] range = [1, 2, 3];
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const actual = foldl!((acc, x) => acc + x)(range[], 0);
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assert(actual == 6);
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}
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